Z = (score-mean)/SD
.1230 = Z of 1.16
.1251 = Z of 1.15
.1234 = Z of 1.15??
Insert the interpolated Z score and other values in above equation to get the score.
Given a population with a normal distribution, a mean of 100, and a standard deviation of 1, what value has an area of .1234 to its right?
1 answer