Given:

Question

a=5.50m/s^2
t=20.25s
Vi=0m/s
find:d=?
d=Vi+1/2 at^2

Answer 1

To find the distance (d), we can use the equation d = Vi + 1/2 at^2.
Given that Vi (initial velocity) is 0 m/s, a (acceleration) is 5.50 m/s^2, and t (time) is 20.25 s, we can substitute these values into the equation:

d = 0 + 1/2 (5.50) (20.25)^2

Simplifying further:
d = 0 + 1/2 (5.50) (410.0625)

d = 0 + 1/2 (2255.34375)

d = 0 + 1127.671875

Therefore, d ≈ 1127.67 meters.