assuming the Hydrogen gas is ideal, we can use the formula:
(V1)/(T1) = (V2)/(T2)
where
V1 = initial volume
T1 = initial temperature (units in Kelvin)
V2 = final volume
T2 = final temperature (units in Kelvin)
since the given temp are in degree Celsius, we first convert it to Kelvin by adding 273:
T1 = 27 + 273 = 300 K
T2 = 42 + 273 = 315 K
substituting to the formula:
90 / 300 = (V2) / 315
V2 = 94.5 mL
hope this helps~ :)
given 90 ml of Hydrogen gas collected with the temperature is 27 degrees C. What
volume will the Hydrogen occupy at 42 C ?
1 answer