Question

given ç 1to-1 f(x)dx=0 and ç 1to0 f(x)dx=5, compute the following
a.ç 0to-1 f(x)dx
b.ç 0to1 3f(x)dx=0
c.ç 1to-1 (f(x)+7)dx=0

Answer 1

ç is the integral sign

Answer 2

Using I for integral,

I f(x) dx [1,-1] = I f(x) dx [1,0] + I f(x) dx [0,-1]

I f(x) dx [0,1] = -I f(x) dx [1,0]

I 3f(x) dx = 3 * I f(x) dx

I (f(x)+7) dx = I f(x) dx + I 7 dx

Now just plug and chug...