Given 120mL of neon gas at 40 degrees C, what teperature corresponds to a volume that has been decreased by 30mL?
(P1V2)/T1 = (P2V2)/T2.
Use V1 = 120 mL and V2 = 120-30=90 mL
Don't forget to change degrees C to Kelvin.
Kelvin = 273 + oC.
(P1V2)/T1 = (P2V2)/T2.
Use V1 = 120 mL and V2 = 120-30=90 mL
Don't forget to change degrees C to Kelvin.
Kelvin = 273 + oC.
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2 answers
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