q = mass x specific heat x delta T
q = 231
mass = 10.8
sp.h. = 6.55
dT= solve
given 10.8 grams of substance y,if the substance absorbs 231 kilojoules of energy and the specfic heat of substance is 6.55 J/g*0C what is the heat change
2 answers
3.265 deg. C
2 answers