GIVE THE EMPIRICAL FORMULAE OF THE HIGHEST HYDRIDE AND HIGHEST FLUORIDE OF UNUNHEXIUM, EXPLAINING HOW YOU ARRIVED AT YOUR CONCLUSIONS

Question

Here is the web site for a very good periodic table. Look for element #116, Uuh. Elements in the periodic table have similar chemical properties if they are in the same group. Therefore, the chemistry of S and Se should be similar to that of Uuh. So the hydride and fluoride should be about the same formula as you might find for S or Se.

don't understand how you find the hydride and fluoride

do you have a formula

sorry

The element Uuh should have a similar chemistry to the other elements in that group; that is, S, Se, etc. If you know what the hydride of S and Se are and the fluoride of S and Se are, then you should be able to make an educated guess as to the formula for UuhFx and UuhHx.

When you go to the web site to look at the periodic table, click on S and Se and see what the hydrides and fluoride formulas are. They are listed there.

is it UuhF6 and H2Uuh?

but i'm guessing and can't explain how i got there

Sure you can. And you aren't guess although you may be making an educated guess. Uuh is in the same column as O, S, Se, Po, etc.
We write H2O for water. H2S for hydrogen sulfide, H2Se for hydrogen selenide. I would make an educated guess that this would be H2Uuh.

I know sulfur forms SF6 so I would go with UuhF6 as an educated guess.

Thank you x

Gemma, I used to live in the IOW till 2005. maybe we know each other.

I used to live on the isle of wight too, went to the college there and lived their for 9 years.

Answer 1

Of the mean, median, and mode, which measure of center is most affected by outliers? Explain your reasoning including an example with at least 10 data points.

Answer 2

The measure of center that is most affected by outliers is the mean.

The reason for this is that the mean takes into account every data point, and outliers can greatly skew the calculation. For example, let's consider the following data set of 10 salaries in thousands of dollars:

$20, $25, $30, $35, $40, $45, $50, $55, $60, $200

The median of this data set is $42.50, which is not affected by the outlier of $200. The mode of this data set is not applicable since there are no repeated values.

However, the mean of this data set is $45, and it is greatly affected by the outlier of $200. The addition of this one outlier has increased the mean by $15, which is a significant change relative to the other data points.

Therefore, in situations where there are outliers, it is often more useful to use the median as the measure of center instead of the mean.