1. if you meant
g(x) = 5/(x^2 - 25)
then the domain is the set of real numbers , except x ≠ ±5
2.
f(t) = 3t^2 + 5t + 2
domain is any real number of t
3. h(x) = √(5x-2)
we cannot take the square root of a negative, so
5x - 2 ≥ 0
5x ≥ 2
x ≥ 2/5
so the domain is any real number with x ≥ 2/5
Give the domain of the function.
1. g(x)= 5/ x^2 -25
= all real numbers
2.f(t)= 3t^2+5t+2
= Negative
3. h(x)= squareRoot of ; 5x-2
= All real numbers
1 answer
1 answer