if the building's height is h,
the distance to P, call it x,
tan60° = h/x
x = h/√3
from h/3, the angle θ has
tanθ = (h/3)/(h/√3) = 1/√3
θ = 30°
give me the solution from the top of a building the angle of depression of a point on the same horizontal plane with the base of the building is observed to be 60 degree what will be the angle of depression of the same point when viewed from a position one third of the way up the building
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