Example:
Data set: 2, 4, 6, 8, 10
Mean = (2+4+6+8+10)/5 = 6
Absolute deviations:
|2-6| = 4
|4-6| = 2
|6-6| = 0
|8-6| = 2
|10-6| = 4
MAD = (4+2+0+2+4)/5 = 2.4
In this example, the mean absolute deviation is 2.4.
give me examples for all of them
absolute deviation – the absolute value of the distance from the data point to the mean
mean absolute deviation (MAD) – the sum of the absolute deviations divided by the number of data values
7 answers
what about M.A.D mean absolute deviation – the sum of the absolute deviations divided by the number of data values
Example:
Data set: 5, 8, 10, 12, 15
Mean = (5+8+10+12+15)/5 = 10
Absolute deviations:
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
MAD = (5+2+0+2+5)/5 = 2.8
In this example, the mean absolute deviation is 2.8.
Data set: 5, 8, 10, 12, 15
Mean = (5+8+10+12+15)/5 = 10
Absolute deviations:
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
MAD = (5+2+0+2+5)/5 = 2.8
In this example, the mean absolute deviation is 2.8.
what about
Data set: 5, 8, 10, 12, 15
Mean = (5+8+10+12+15)/5 = 10
Absolute deviations:
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
MAD = (5+2+0+2+5)/5 = 2.8
In this example, the mean absolute deviation is 2.8.
Data set: 5, 8, 10, 12, 15
Mean = (5+8+10+12+15)/5 = 10
Absolute deviations:
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
MAD = (5+2+0+2+5)/5 = 2.8
In this example, the mean absolute deviation is 2.8.
Yes, that's correct. In the example provided, the mean absolute deviation (MAD) is calculated as 2.8.
what about
absolute deviation – the absolute value of the distance from the data point to the mean
absolute deviation – the absolute value of the distance from the data point to the mean
In the example provided for the data set {5, 8, 10, 12, 15} with a mean of 10, the absolute deviations from the mean for each data point are as follows:
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
The absolute deviation is 5 for the data point 5, 2 for the data points 8 and 12, and 0 for the data point 10.
|5-10| = 5
|8-10| = 2
|10-10| = 0
|12-10| = 2
|15-10| = 5
The absolute deviation is 5 for the data point 5, 2 for the data points 8 and 12, and 0 for the data point 10.