give exact and approximate to three decimals places x^2+8x+16=25 Please help me solve this

Answer 1

x^2+8x+16-25 = 0,
x^2+8x-9 = 0,
(x+9(x-1) = 0,

x+9 = 0,
X = -9.

x-1 = 0,
X = 1.

Solution set: X = -9, and X = 1.