Give exact and approximate solutions to three decimal places for y.

Question

y^2-6y+9=64

If anyone can help with this problem I would really appriciate it. Thanks

Answer 1

Rewrite it in standard form
y^2 -6y -55 = 0
and then factor:
(y+11)(y-5) = 0
The answers are exact integers, so you don't have to worry about decimal places, unless that want you to write 5 as 5.000, etc.

Answer 2

Thank you for your help. So just to make sure its 11, 5 right. 5 is positive not negative??