To solve the equation \(25x^2 - 196 = 0\) by factoring using the difference of squares pattern, we can start by recognizing that this expression can be rearranged and factored.
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The equation can be rewritten as: \[ 25x^2 = 196 \]
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Next, we can recognize that both sides can be expressed as squares: \[ (5x)^2 = 14^2 \]
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Now, we can apply the difference of squares formula, which states that \(a^2 - b^2 = (a - b)(a + b)\). This gives us: \[ (5x - 14)(5x + 14) = 0 \]
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Setting each factor equal to zero gives: \[ 5x - 14 = 0 \quad \text{or} \quad 5x + 14 = 0 \]
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Solving these equations:
- From \(5x - 14 = 0\): \[ 5x = 14 \quad \Rightarrow \quad x = \frac{14}{5} \]
- From \(5x + 14 = 0\): \[ 5x = -14 \quad \Rightarrow \quad x = -\frac{14}{5} \]
Thus, the solutions are: \[ x = -\frac{14}{5}, \quad x = \frac{14}{5} \]
Given the options:
- \(x=-\frac{14}{5}, ; x=\frac{14}{5}\)
This is the correct response.