Question
Ginger was asked to solve 16x2−1 by using the difference of two squares pattern. What is/are the correct solution(s)?(1 point) Responses x=14 x is equal to 1 fourth x=116 x is equal to 1 over 16 x=−14 , x=14 x is equal to negative 1 fourth, x is equal to 1 fourth There is no solution for x because the difference of squares pattern does not apply.
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Answered by
GPT-4o mini
To solve the expression \(16x^2 - 1\) using the difference of squares pattern, we recognize that it can be factored as follows:
\[
16x^2 - 1 = (4x)^2 - (1)^2
\]
This can be factored into:
\[
(4x - 1)(4x + 1) = 0
\]
Next, we set each factor to zero to find the solutions for \(x\):
1. \(4x - 1 = 0\)
- Solving for \(x\):
\[
4x = 1 \quad \Rightarrow \quad x = \frac{1}{4}
\]
2. \(4x + 1 = 0\)
- Solving for \(x\):
\[
4x = -1 \quad \Rightarrow \quad x = -\frac{1}{4}
\]
Thus, the solutions are:
\[
x = \frac{1}{4} \quad \text{and} \quad x = -\frac{1}{4}
\]
Now, looking at the responses you provided, the correct solution(s) would be:
- \(x = -\frac{1}{4}, x = \frac{1}{4}\)
So, you would select the response that includes both of these values.
\[
16x^2 - 1 = (4x)^2 - (1)^2
\]
This can be factored into:
\[
(4x - 1)(4x + 1) = 0
\]
Next, we set each factor to zero to find the solutions for \(x\):
1. \(4x - 1 = 0\)
- Solving for \(x\):
\[
4x = 1 \quad \Rightarrow \quad x = \frac{1}{4}
\]
2. \(4x + 1 = 0\)
- Solving for \(x\):
\[
4x = -1 \quad \Rightarrow \quad x = -\frac{1}{4}
\]
Thus, the solutions are:
\[
x = \frac{1}{4} \quad \text{and} \quad x = -\frac{1}{4}
\]
Now, looking at the responses you provided, the correct solution(s) would be:
- \(x = -\frac{1}{4}, x = \frac{1}{4}\)
So, you would select the response that includes both of these values.
Answered by
GPT-4o mini
The correct response to select is:
**"x = -1/4, x = 1/4"**
This encompasses both solutions found by factoring the expression \(16x^2 - 1\).
**"x = -1/4, x = 1/4"**
This encompasses both solutions found by factoring the expression \(16x^2 - 1\).
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