Asked by dee
GG.1 Is (x, y) a solution to the system of equations?
N46
Is (
–
4,4) a solution to this system of equations?
y=
–
1
4
x+3
y=x+9
N46
Is (
–
4,4) a solution to this system of equations?
y=
–
1
4
x+3
y=x+9
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine whether the point \((-4, 4)\) is a solution to the given system of equations, we need to substitute \(x = -4\) and \(y = 4\) into each equation and check if both equations hold true.
The system of equations is:
1. \(y = -\frac{1}{4}x + 3\)
2. \(y = x + 9\)
**Check the first equation:**
Substituting \(x = -4\) into the first equation:
\[
y = -\frac{1}{4}(-4) + 3
\]
\[
y = 1 + 3
\]
\[
y = 4
\]
This matches the \(y\)-value provided, so \((-4, 4)\) satisfies the first equation.
**Check the second equation:**
Substituting \(x = -4\) into the second equation:
\[
y = -4 + 9
\]
\[
y = 5
\]
This does not match the \(y\)-value provided (which is \(4\)). Thus, \((-4, 4)\) does not satisfy the second equation.
**Conclusion:**
The point \((-4, 4)\) is not a solution to the system of equations because it does not satisfy both equations.
The system of equations is:
1. \(y = -\frac{1}{4}x + 3\)
2. \(y = x + 9\)
**Check the first equation:**
Substituting \(x = -4\) into the first equation:
\[
y = -\frac{1}{4}(-4) + 3
\]
\[
y = 1 + 3
\]
\[
y = 4
\]
This matches the \(y\)-value provided, so \((-4, 4)\) satisfies the first equation.
**Check the second equation:**
Substituting \(x = -4\) into the second equation:
\[
y = -4 + 9
\]
\[
y = 5
\]
This does not match the \(y\)-value provided (which is \(4\)). Thus, \((-4, 4)\) does not satisfy the second equation.
**Conclusion:**
The point \((-4, 4)\) is not a solution to the system of equations because it does not satisfy both equations.
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