tanx-sqr3=2tanx
tanx = -√3
tanx is negative , so x must be in quads II or IV
I know tan 60° = √3
so x = 180-60= 120°
or
x = 360-60 = 300°
in radians that would be 2π/3 or 5π/3
2sin^2 x + sinx = 0
sinx(2sinx + 1) = 0
sinx = 0 or sinx = -1/2
sinx = 0 ----> x = 0, 180° or 360°
or sinx = -1/2
since sinx is negative, x must be in III or IV
I know sin 30 = +1/2
x = 180+30 = 210 or x = 360-30 = 330°
so x = 0,180, 360,210 , or 330
Getting ready for trig semester finals. Can't figure out how they are simplifying these equations. (these are the review not actual test)
tanx-sqr3=2tanx
and
2sin^2+sinx=0
3 answers
I get the second one, but the first I don't. What identity are you using for the first to get from line one to two?
just rearranging terms, collecting tan's on the left, numbers on the right. Pretty mysterious, eh?
1 answer