Use PV = nRT
Solve for n= number of moles.
Then n = grams/molar mass. Solve for molar mass.
Geraniol is a compound found in rose oil that is used in perfumes. What is the molas mass of geraniol if its vapor has a density of 0.480 g/L at a temperature of 260.0 degrees Celsius and a pressure of 0.140 atm???
6 answers
What would I use for volume (V)?
Sorry, I didn't notice that. The problem gives density so we take PV = nRT and work on it.
Since n = grams/molar mass we substitute to obtain
PV = gRT/molar mass and
pV*molar mass = gRT, then
P*molar mass = (g/V)RT but g/V = density so
p*molar mass = density*RT
That should help.
Since n = grams/molar mass we substitute to obtain
PV = gRT/molar mass and
pV*molar mass = gRT, then
P*molar mass = (g/V)RT but g/V = density so
p*molar mass = density*RT
That should help.
Thank you!!
Hope this helps!!!
D= 0.480 g/l
T= 260.0°C+ 273= 533K
P= 0.140 ATM
R(constant; always 0.08206)
M(molar mass)= DRT/P
M= 0.480× 0.08206× 533/ 0.140= 149.96 g/mol
Molar mass of geraniol= 149.96 g/mol
D= 0.480 g/l
T= 260.0°C+ 273= 533K
P= 0.140 ATM
R(constant; always 0.08206)
M(molar mass)= DRT/P
M= 0.480× 0.08206× 533/ 0.140= 149.96 g/mol
Molar mass of geraniol= 149.96 g/mol
The answer is correct sir
1 answer