The equation that represents the situation to find the cost of all adult and student tickets sold is:
4a + 2.50s = 2820
The equation that represents the situation for 900 tickets sold is:
a + s = 900
Using the above system of equations, we can determine that adult tickets sold would be 400 and student tickets sold would be 500.
Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost $4 and student tickets cost $2.50. The school makes $2,820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. (7 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. Response area a + Response area s = Response area 900 tickets are sold for the spring fling. Write an equation to represent this situation. a + Response area = Response area Use the above system of equations to determine how many adult and student tickets were sold. Response area adult tickets and Response area student tickets were sold.
5 answers
the last one is incorrect
I apologize for the mistake. Thank you for pointing it out. Let's correct it:
The equation that represents the situation for 900 tickets sold is:
a + s = 900
Using the above system of equations, we can determine that adult tickets sold would be 900 - s, and student tickets sold would be s.
The equation that represents the situation for 900 tickets sold is:
a + s = 900
Using the above system of equations, we can determine that adult tickets sold would be 900 - s, and student tickets sold would be s.
how did you find that answer
My apologies for the confusion caused. To find the solution, we can use the given information and the system of equations provided.
The equation representing the cost of all adult and student tickets sold is:
4a + 2.50s = 2820
The equation representing the total number of tickets sold is:
a + s = 900
To determine the number of adult and student tickets sold, we can solve this system of equations simultaneously. Here's how we can do it:
1. Solve the second equation for a:
a = 900 - s
2. Substitute this expression for a into the first equation:
4(900 - s) + 2.50s = 2820
3. Simplify and solve for s:
3600 - 4s + 2.50s = 2820
-1.50s = 2820 - 3600
-1.50s = -780
s = -780 / -1.50
s = 520
4. Substitute the value of s back into the second equation to find a:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, the number of adult tickets sold is 380 and the number of student tickets sold is 520.
The equation representing the cost of all adult and student tickets sold is:
4a + 2.50s = 2820
The equation representing the total number of tickets sold is:
a + s = 900
To determine the number of adult and student tickets sold, we can solve this system of equations simultaneously. Here's how we can do it:
1. Solve the second equation for a:
a = 900 - s
2. Substitute this expression for a into the first equation:
4(900 - s) + 2.50s = 2820
3. Simplify and solve for s:
3600 - 4s + 2.50s = 2820
-1.50s = 2820 - 3600
-1.50s = -780
s = -780 / -1.50
s = 520
4. Substitute the value of s back into the second equation to find a:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, the number of adult tickets sold is 380 and the number of student tickets sold is 520.
1 answer