the perimeter of the real sail ...
need the other side:
which is √(13^2 - 8^2) = √105
so perimeter of real sail = √105 + 13 + 8 =21 + √105
so the perimeter of the model sail = (21 + √105)/32
George is building a model of his father's sailboat with a scale factor of 1:32. The actual sail is in the shape of a right triangle with a base of 8 meters and a hypotenuse of 13 meters. What will be the approproximate perimeter of the sail on the model boat?
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