K=ln(3.6/1.2)/timeelapsed
k=ln(3)/(1307-1056)=ln(3)/2:11
k= ln(3)/(131min) or ln3/2.18 hr
Gent dose at 10:26am over 30 minutes and levels were reported as 3.6 at 13:07 and 1.2 at 16:59. Calculate k.
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4 answers
K=0.50 is this correct?
yes, but you need to include units:
.50/hr
.50/hr
Thank you!