To find the amount of money in the account after one year using the formula \( P(t) = 1200 e^{0.16t} \), we substitute \( t = 1 \):
\[ P(1) = 1200 e^{0.16 \times 1} \] \[ P(1) = 1200 e^{0.16} \]
Now, we need to calculate \( e^{0.16} \). The value of \( e^{0.16} \) can be computed using a calculator:
\[ e^{0.16} \approx 1.17351 \]
Now, substitute this value back into the equation:
\[ P(1) = 1200 \times 1.17351 \] \[ P(1) \approx 1408.21 \]
Thus, the amount of money in the account after one year is approximately $1,408.21.