To determine the amount of money in Gabriela's account after one year using the formula for continuously compounding interest, we can plug in the values into the formula \( P(t) = 1200 e^{0.16t} \).
Here, \( t = 1 \) (one year) and the formula becomes:
\[ P(1) = 1200 e^{0.16 \times 1} \]
Calculating \( e^{0.16} \) first:
\[ e^{0.16} \approx 1.17351 \quad (\text{using a calculator}) \]
Now substituting back into the formula:
\[ P(1) = 1200 \times 1.17351 \approx 1408.21 \]
Thus, the amount of money in the account after one year is approximately $1,408.21.