g(x)=(x^2+2x+1)/(x^2-x-6)

1. Find any holes in the graph of g(x)
2. Find any horizontal or oblique asymptote for the graph.
3. Determine where (if any at all) the graph of g(x) crosses the horizontal or oblique asymptote.

1 answer

since the denominator is (x-3)(x+2), there are asymptotes (and hence, holes) at x = -2,3

as x->∞, g(x)->1, so the horizontal asymptote is at g=1

g(-7/3) = 1
Similar Questions
  1. g(x)=(2x^3+x^2-18x-9)/(x^2+x-6)A. Find the vertical asymptotes. b. find any holes. c. find any oblique or horizontal asymptotes.
    1. answers icon 1 answer
  2. P(x) = (2x^3+x^2-18x-9)/(x^2-x-6)1.Find any holes in the graph of P(x) 2.Find any horizontal or oblique asymptote 3.Determine
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions