What second line? What first line? That is a parabola. Its slope is
df(x)/dx = 2x - 12
function: f(x)=x^2-12x+35
Interval [6,6.5]
How do you find the slope of the second line? Can you show this in the formula? and what would the answer be rounded to four decimal places as needed.
2 answers
you give an interval. If you want the slope of the line joining two points on the curve for that interval, then as you recall from your long-ago Algebra I, the slope
m = ∆y/∆x = (f(6.5)-f(6))/(6.5-6)
m = ∆y/∆x = (f(6.5)-f(6))/(6.5-6)