Question

Function 1: f(x) = 4x + 2
Function 2: ?
Compare the two functions and identify the y values of the y intercepts Which function has the smaller value
On the graph is straight line with points (1,-6),(-1,2) it crosses the y axis at (0,-2) and x axis at (0.5,0)
Options
Function 1 (0,2); Function 2: (0,-2). Function 2 has the smallest value
Function 1: (-1,0); Function 2: (-1,0). They have identical values
Function 1: (0,-2); Function 2: (0,2). Function 2 has the smallest value
Function 1: (-2,0); Function 2: (2,0). Function 1 has the smallest value

Answer 1

To analyze the two functions and identify their y-intercepts, let's first rewrite the information provided about each function clearly.

**Function 1:** \( f(x) = 4x + 2 \)

To find the y-intercept of Function 1, we set \( x = 0 \):
\[
f(0) = 4(0) + 2 = 2
\]
So, the y-intercept of Function 1 is \( (0, 2) \).

**Function 2:** Based on your description of the line with points (1, -6) and (-1, 2) crossing the y-axis at (0, -2), we can conclude:
- The y-intercept of Function 2 is \( (0, -2) \).

Now let's compare the two y-intercepts:
- **Function 1 y-intercept:** \( (0, 2) \)
- **Function 2 y-intercept:** \( (0, -2) \)

To identify which value is smaller, we can see that:
- The y-value of Function 1 at the y-intercept is **2**.
- The y-value of Function 2 at the y-intercept is **-2**.

Thus, Function 2 has the smaller y-intercept value.

From the options:
1. **Function 1:** (0, 2); **Function 2:** (0, -2). **Function 2 has the smallest value**. ✅
2. Function 1: (-1, 0); Function 2: (-1, 0). They have identical values. ❌
3. Function 1: (0, -2); Function 2: (0, 2). Function 2 has the smallest value. ❌
4. Function 1: (-2, 0); Function 2: (2, 0). Function 1 has the smallest value. ❌

The correct option is:
**Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smallest value.**