To analyze the two functions and identify their y-intercepts, let's first rewrite the information provided about each function clearly.
Function 1: \( f(x) = 4x + 2 \)
To find the y-intercept of Function 1, we set \( x = 0 \): \[ f(0) = 4(0) + 2 = 2 \] So, the y-intercept of Function 1 is \( (0, 2) \).
Function 2: Based on your description of the line with points (1, -6) and (-1, 2) crossing the y-axis at (0, -2), we can conclude:
- The y-intercept of Function 2 is \( (0, -2) \).
Now let's compare the two y-intercepts:
- Function 1 y-intercept: \( (0, 2) \)
- Function 2 y-intercept: \( (0, -2) \)
To identify which value is smaller, we can see that:
- The y-value of Function 1 at the y-intercept is 2.
- The y-value of Function 2 at the y-intercept is -2.
Thus, Function 2 has the smaller y-intercept value.
From the options:
- Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smallest value. ✅
- Function 1: (-1, 0); Function 2: (-1, 0). They have identical values. ❌
- Function 1: (0, -2); Function 2: (0, 2). Function 2 has the smallest value. ❌
- Function 1: (-2, 0); Function 2: (2, 0). Function 1 has the smallest value. ❌
The correct option is: Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smallest value.
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