Fully simplify and write your answer in exponential form with positive exponents only.

y^-8*y^-2*y^-5

1 answer

To simplify the expression \( y^{-8} \cdot y^{-2} \cdot y^{-5} \), you can use the property of exponents which states that when you multiply powers with the same base, you add their exponents:

\[ y^{-8} \cdot y^{-2} \cdot y^{-5} = y^{-8 + (-2) + (-5)} \]

Now, calculate the sum of the exponents:

\[ -8 - 2 - 5 = -15 \]

So, we have:

\[ y^{-8} \cdot y^{-2} \cdot y^{-5} = y^{-15} \]

To express this with positive exponents, we use the property that \( y^{-n} = \frac{1}{y^n} \):

\[ y^{-15} = \frac{1}{y^{15}} \]

Thus, the fully simplified expression is:

\[ \frac{1}{y^{15}} \]