fully reduce this fraction

2(x+1)/6(x+2)

1 answer

The fraction can be fully reduced by factoring out a common factor from the numerator and denominator.

2(x+1)/6(x+2) = 2(x+1)/6(x+2)

Now, factor out a 2 from the numerator and a 6 from the denominator:

2(x+1)/6(x+2) = (2/2)(x+1)/(6/2)(x+2)

Simplify:

= (1)(x+1)/(3)(x+2)

= (x+1)/(3x+6)

Therefore, the fully reduced fraction is (x+1)/(3x+6).