The fraction can be fully reduced by factoring out a common factor from the numerator and denominator.
2(x+1)/6(x+2) = 2(x+1)/6(x+2)
Now, factor out a 2 from the numerator and a 6 from the denominator:
2(x+1)/6(x+2) = (2/2)(x+1)/(6/2)(x+2)
Simplify:
= (1)(x+1)/(3)(x+2)
= (x+1)/(3x+6)
Therefore, the fully reduced fraction is (x+1)/(3x+6).
fully reduce this fraction
2(x+1)/6(x+2)
1 answer