If the reaction is
3CuCl2 + 2Al = 2AlCl3 + 3Cu
looks like you have 3 moles of copper for every 2 moles of aluminum.
You have 2 moles of aluminum.
From the Periodic Table, 1 mole of aluminum weighs 27.0 g.,
Therefore;
If 54.0 g of aluminum are placed into the beaker to react with copper(II) chloride, how many grams of the metal product will be produced?
1 answer