acceleration= changevelocty/time= (10m/s-2m/s)/5sec=8/5 m/s^2
distance= initialvel*time+1/2 acceleration*time^2
= 2*5+ 1/2*8/5*25=10+20=30m
From the below information
Speed(m/sec) 2m at 0 sec, 4m at 2 sec, 6m at 3 sec, 8m at 4 sec, 10m at 5 sec.
Calculate acceleration.
Distance (I am getting answer as 27m but as per book it is 30m. Here as per table velocity is not uniform.) Plz confirm me the correct answer.
Thank you.
3 answers
Thank you Bob.
Can you please explain while I tried finding distance through area of triangles I did not get the same answer. With the given table I got two triangles shapes. One is 2 to 4 with 2 sec and other one is from 4 to 10 with time from 2sec to 5 sec. Rest of the shape I got is rectangles 0 to 4 with time 2 sec to 5 sec and 0 to 2 with time 0 to 2 sec.
Plz share your precious time. Thank you.
Can you please explain while I tried finding distance through area of triangles I did not get the same answer. With the given table I got two triangles shapes. One is 2 to 4 with 2 sec and other one is from 4 to 10 with time from 2sec to 5 sec. Rest of the shape I got is rectangles 0 to 4 with time 2 sec to 5 sec and 0 to 2 with time 0 to 2 sec.
Plz share your precious time. Thank you.
Hi Bob can u plz reply
2 answers