From point AandB on level ground,the angle of elevation of the top of a building are 25degree and 37degree respectively.if |AB|〓57m,calculate,to the nearest metre,the distances of the top of the building from AandB if they are both on thesame side of the building.

Answer 1

Call T the top
call G the bottom

T G B is a right triangle
37 at B, 90 at G, thus 53 at BTG

TGA is a right triangle
25 at A, 90 at G, thus 65 at ATG
thus 122 at ABT

law of sines:
sin 25 / BT = sin 12/ 57
so BT = 156 meters (first answer)

now angle ABT = 180 - 12 - 25
= 143
so
sin 143 /AT = sin12/57
AT = 164 meters, second answer

Answer 2

thus 143 at ABT see a few lines down

Answer 3

if you don't like the law of sines, just study the tan/cot functions. You can easily see that the height h can be found from

h cot25° - h cot37° = 57

Answer 4

25+37

= 62

Answer 5

Plz solve

Answer 6

How do u get 122

Answer 7

That is called mathemagic