From five faculty members and four students, a committee of four is to be chosen that includes two students and two faculty members. In how many ways can this be done?

Is it combinations problem? I think it is, so I would put 9 nCr 4.

Question

From five faculty members and four students, a committee of four is to be chosen that includes two students and two faculty members.  In how many ways can this be done?

Please show more than one approach.

Tamar · Answer

I would put in 9 nCr 4 in a calculator. Am I right?

Asenath · Answer

From five faculty members and four students, a committee of four is to be chosen that includes two students and two faculty members. In how many ways can this be done?

Is it combinations problem? I think it is, so I would put 9 nCr 4.

Satake · Answer

Yeah, but two committee members must be chosen from faculty and two from students, then you have to start by separating the two groups and working from there.

By the way, if I find out who you are, you get a zero for the project.

Happy Monday!