base will be 12 - 2x by 12-2x, height will be x
V = x(12-2x)^2
range of x: 0 < x < 6
From each corner of a square of tin, 12 cm on a side, small squares of side x are removed and the edges are turned up to form an open box. Express the volume V(cm3) as a function of x. Determine the range of x.
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