from an observation point the angle of depression of two boats in line with this point are found to 30 degrees and 45 degrees .find the distance between the two boats if the point of observation is 4000 feet high.
2 answers
Only your specific subject is needed ... not your school's name. =)
Did you make a diagram ?
On mine I labeled the top of the observation point A and its bottom as B
The farter boat as P and the closer boat as Q
So we have two right-angled triangles with the angle at P as 30° and the angle at Q as 45°
in triangle AQB ,
tan 45° = 4000/QB
QB = 4000/tan45
in triangle APB,
tan 30 = 4000/PB
PB = 4000/tan30
distance between boats = PB - QB
= .....
I will let you finish it
(you should get 2928.2 )
On mine I labeled the top of the observation point A and its bottom as B
The farter boat as P and the closer boat as Q
So we have two right-angled triangles with the angle at P as 30° and the angle at Q as 45°
in triangle AQB ,
tan 45° = 4000/QB
QB = 4000/tan45
in triangle APB,
tan 30 = 4000/PB
PB = 4000/tan30
distance between boats = PB - QB
= .....
I will let you finish it
(you should get 2928.2 )