prob of 2 red cards = (26/52)(25/51) = 25/102
prob of red and black = 2(26/52)(26/51) = 26/51
or
prob two reds = C(26,2)/C(52,2) = 25/102
prob rd and black = C(26,1) x C(26,1)/C(52,2) = 26/51
From a standard deck of cards, two cards are randomly drawn, one after the other without replacement. The color of each car is noted. Which is less likely to occur: two red cards or a red card and a black card? Explain.
1 answer