Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two values for the Z scores.
From a sample with n equals=24, the mean number of televisions per household is 3 with a standard deviation of 1 television. Using Chebychev's Theorem, determine at least how many of the households have between 1 and 5 televisions.
3 answers
45
24