since the balls are replaced, the draws are independent events. Just multiply all the probabilities:
5/10 * 3/10 * ...
From a sample set of 10 colored balls--5 green, 3 red and 2 yellow-- 5 are chosen at random WITH replacement. What is the probability that the result will be: green, red, yellow, red, green? Write your answer as a four place decimal number. p(G,R,Y,R,G)
2 answers
.0045