Fred Flintstone’s club–ax is made up of two parts: an uniform 2.5 kg stick and a symmetrical 10 kg stone attached to the end of the stick. The dimensions of the club-ax are shown in the figure. How far is the center of mass from the handle end of the club-ax? Express your answer in cm.
Handle: 80cm
Stone: 18cm
2 answers
Hint: Assume stone is drilled and the stick passes through it
the c-o-m is between the c-o-m of the stick and the c-o-m of the stone
the centers of mass for the stick and the stone are in their physical centers
using some distance (d) from the center of the stick toward the center of the stone
... 2.5 * d = 10 * (40 - 18/2 - d)
find d ... add to 40 cm
the centers of mass for the stick and the stone are in their physical centers
using some distance (d) from the center of the stick toward the center of the stone
... 2.5 * d = 10 * (40 - 18/2 - d)
find d ... add to 40 cm