consider the takeoff to be at (0,0). The height of the skier is thus
y = vt - 4.9t^2
maximum height is thus reached at t = v/9.8
y(v/9.8) = v*v/9.8 - 4.9(v/9.8)^2
= v^2/9.8 - v^2/(4*4.9)
= v^2/9.8 (1 - 1/2)
= v^2/19.6
Since the max height is directly proportional to the square of the takeoff velocity, the ratio of the max heights achieved by Fred and George is (20/8.5)^2
Since you give no data regarding the angle of takeoff, we cannot calculate any absolute values, but we do have the ratio.
Fred and George who are identical twins (same body mass) are competing in aerial skiing. Fred hits the take off with a speed of 20 whereas George has a speed of 8.5. How much higher will Fred go?
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