Since both girls have the genotype FF for freckles, they both have two dominant alleles for the freckle trait. If either one marries a man with no freckles, who would have the genotype ff (since he has no freckles), the potential offspring's genotypes would be:
- Mother: FF
- Father: ff
When we set up a Punnett square, we can see the possible genotypes of their children:
F | F
--------------
f | Ff | Ff
--------------
f | Ff | Ff
All offspring will have the genotype Ff, which indicates they will all express the dominant trait of having freckles.
Therefore, the chances that their children will have freckles are 100%.
So the correct response is: D 100%