The parabola y^2 = 4px has focus at x=p.
You have a parabola
y^2+6y = 3x-3
(y+3)^2 = 3(x+2)
So, its focus is at
(x+2) = 3/4
x = -5/4
and since the line y+3 = 0 is the axis of symmetry, the focus is at (-5/4,-3) as desired.
Franco is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satellite can be modeled by y^2+6y-3x+3=0, where x and y are modeled in inches. He realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?
This is the answer(–1.25, –3)but i do not know how to solve.
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