To add the fractions \(-1 \frac{3}{10} + (-4 \frac{2}{15})\), we first convert the mixed numbers to improper fractions.
-
Convert \(-1 \frac{3}{10}\): \[ -1 \frac{3}{10} = -\left(\frac{10 \times 1 + 3}{10}\right) = -\left(\frac{10 + 3}{10}\right) = -\left(\frac{13}{10}\right) \]
-
Convert \(-4 \frac{2}{15}\): \[ -4 \frac{2}{15} = -\left(\frac{15 \times 4 + 2}{15}\right) = -\left(\frac{60 + 2}{15}\right) = -\left(\frac{62}{15}\right) \]
Now we need to add \(-\frac{13}{10}\) and \(-\frac{62}{15}\). To do this, we first find a common denominator. The least common multiple of 10 and 15 is 30.
-
Convert both fractions to have a denominator of 30: \[ -\frac{13}{10} = -\frac{13 \times 3}{10 \times 3} = -\frac{39}{30} \] \[ -\frac{62}{15} = -\frac{62 \times 2}{15 \times 2} = -\frac{124}{30} \]
-
Now, we can add the two fractions: \[ -\frac{39}{30} + -\frac{124}{30} = -\frac{39 + 124}{30} = -\frac{163}{30} \]
Now, \(-\frac{163}{30}\) can also be converted back to a mixed number: \[ -\frac{163}{30} = -5 \frac{13}{30} \]
Thus, the sum of \(-1 \frac{3}{10} + (-4 \frac{2}{15})\) is \(-5 \frac{13}{30}\).