fraction with negative 5 times the quantity 3 minus the cube root of 27 times 2 end quantity as the numerator and 3 as the

Question

denominator

a) six fifths
b) 5
c) negative six fifths
d) −5

Answer 1

To simplify this expression, we can start by simplifying the expression inside the numerator:

3 - cube root of 27 times 2

The cube root of 27 is the same as the cube root of 3^3, which is 3. Therefore, we have:

3 - 3 times 2

Next, we simplify further:

3 - 6

Finally, we simplify the numerator expression:

-3

Therefore, the fraction is:

-3/3

Since -3 divided by 3 is -1, the fraction simplifies to:

-1

So, the correct answer is: d) -5