Let's assume the number is x.
The sum of a number and four is x + 4.
Four times the sum of a number and four is 4(x + 4) = 4x + 16.
Two less than three times the number is 3x - 2.
According to the problem, 4x + 16 = 2(3x - 2).
Simplifying the equation, we get 4x + 16 = 6x - 4.
Bringing the variables to one side, we have 6x - 4x = 16 + 4.
Simplifying, we get 2x = 20.
Dividing both sides by 2, we get x = 10.
Therefore, the solution to the problem is x = 10.
Four times the sum of a number and four is the same as two multiplied by two less than three times the number. What is the solution to this problem?
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