we find h.c.f in all four no. then we get h.c.f=2
then we divide all four no. by h.c.f
then we get 7,9,11,13.w add together these no.
four ribbons measuring 4m,18m,22m and 26m respectively are to be cut into piece of equal length.
1)find the least no. of piece tat can be obtained?
2)what is the length of each piece?
2 answers
Maya have three ribbons measuring 28cm,,70cm,126 Maya wants to cut all the ribbons with the same length without any remaining . Calculate the length in cm of the longest ribbon can be cut off and the number of ribbons obtained