four positive integers form an arithmetic progression . if the product of the first and the last terms is 70 and the second and third terms are 88, find the first term

Answer 1

a(a+3d) = 70
(a+d)(a+2d) = 88

Since 88=8*11, I'd guess that
T2=8 and T3 = 11

so, that makes T1=5 and T3=15

or, you can solve the equations using algebra.