1 kg at (0,0)
2 kg at (0,2)
3 kg at (1,2)
4 kg at (1,0)
total mass = 10 kg
xcg = (1/10)(1*0 +2*0 + 3*1 +4*1) = 7/10
ycg = (1/10)(1*0 +2*2 + 3*2 +4*0) = 1
four particles of masses 1kg, 2kg,3kg, and 4kg are at vertices of a rectangle of sides a and b.if a=1m and b=2m find the location of the center of mass
2 answers
as 1kg