Asked by Naomi
four identical charges (q = +3µC) are arranged in a form of a rectangle. what are the magnitude and direction of the net electric force on the charge in the lower right corner attributable to the other three charges? distances are in meters.
Answers
Answered by
Damon
Hard to say without knowing the distances... In general F = k Q1 Q2 /|R^2| iin direction of R
If horizontal length = a
and vertical height = h
Q is lower right
Q1 is lower left
Q2 is upper left
Q3 is upper right
R is vector from Q to one of the other 3
Rx = x component of R
Ry = y component of R
then
F1x = k Q Q1/a^2
F1y = 0
F2x = [k Q Q2/(a^2+h^2)] [ a/sqrt(a^2+h^2) ]
F2y = -[ k Q Q2/(a^2+h^2) ] [h/sqrt(a^2+h^2) ]
F3x = 0
F3y = -k Q Q3/h^2
F = F1 + F2 + F3
If horizontal length = a
and vertical height = h
Q is lower right
Q1 is lower left
Q2 is upper left
Q3 is upper right
R is vector from Q to one of the other 3
Rx = x component of R
Ry = y component of R
then
F1x = k Q Q1/a^2
F1y = 0
F2x = [k Q Q2/(a^2+h^2)] [ a/sqrt(a^2+h^2) ]
F2y = -[ k Q Q2/(a^2+h^2) ] [h/sqrt(a^2+h^2) ]
F3x = 0
F3y = -k Q Q3/h^2
F = F1 + F2 + F3
Answered by
Anonymous
I do not know
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