Four forces of 10N,8N,6N and 4N act at the same point of an object on bearing 0 degrees,90 degrees,135 degrees and 270 degrees respectively

Answer 1

Fr = 10[0o] + 8[90o] + 6[135o] + 4[270o]=
Resultant force.
X = 10 + 6*Cos135 = 5.76 N.
Y = 8 + 6*sin135 - 4 = 8.24 N.

Tan A = Y/X.
A =

Fr = Y/sinA =