forces in opposite directions subtract from each other
so the "effective forces here are ... 6N north and 2N east
magnitude ... √(6^2 + 2^2)
direction ... [arctan(2 / 6)] east of north
four forces 8N 6n 2n and 4n act on a point O in the directionsnorth east south and west respectively find the magnitude of their result and the direction of their resultant force
2 answers
Force total=8N + 6E + 2S +4W= N (8-2) + E(6-4)= you finish
magnitude = sqrt (6^2+2^2)
direction= arctan E/N=arctan 2/6 E of N
magnitude = sqrt (6^2+2^2)
direction= arctan E/N=arctan 2/6 E of N