To determine which set of equations has (-3, 0) as its solution, we need to find the equation of the line passing through (-3, 8) and (2, -7).
First, calculate the slope:
m = (y2 - y1) / (x2 - x1)
m = (-7 - 8) / (2 - (-3))
m = -15 / 5
m = -3
Now, use the point-slope form of a linear equation:
y - y1 = m(x - x1)
y - 8 = -3(x - (-3))
y - 8 = -3(x + 3)
y - 8 = -3x - 9
y = -3x - 1
So, the equation of the line passing through (-3, 8) and (2, -7) is y = -3x - 1.
Next, check which set of equations contains this equation:
A: y = 4/3x + 8
B: y = -3x - 1
C: y = -2x + 9
D: y = -1/3x + 3
Therefore, the set of equations that has (-3, 0) as its solution is B and D.
Four equations are graphed on the coordinate grid:
A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Line A passes through the ordered pairs negative 8, 5 and 4, negative 7. Line B passes through the ordered pairs negative 3, 8 and 2, negative 7. Line C passes through the ordered pairs 0, 9 and negative 7, negative 5. Line D passes through the ordered pairs 1, 4 and negative 4, negative 1 and is extrapolated further in the quadrant.
Which set of equations has (−3, 0) as its solution? (1 point)
A and B
B and D
B and C
A and D
1 answer